If you’ve been eager to give the AI video creation powers of Google Veo 3 a try, but haven’t had the funds to stretch to a Google AI Pro (or Ultra) subscription, now’s your chance: Google is giving all Gemini users a taste of the Veo 3 engine this weekend.
As per a Google Gemini App post on social media (via 9to5Google), free users can get three Veo 3 video generations this weekend without paying anything. The offer lasts until 10pm PT Sunday (that’s 1am ET / 6am BST / 3pm AEST on Monday).
The only information we have is that post – so it’s not clear if this applies everywhere in the world, or just the US. Your best bet is to give it a go in Gemini and see what happens, though with only three generations available, choose your words carefully.
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If you do subscribe to Google AI Pro ($19.99 / £18.99 / AU$32.99 per month), then you get three video generations per day, normally. Higher quality videos can also be created by paying users through Google’s online Flow video editor.
Prompt engineering
3 free video generations.1 weekend only.https://t.co/x0H7mWra9mEnds Sunday 10pm PT.August 22, 2025
We’ve written extensively about what you can do with Veo 3 in Gemini. One of the tricks you can try is turning a still image into a video: just describe what you want to happen in the picture, and after a couple of minutes of thinking, Veo 3 will do the rest.
You can also start from scratch of course. Try and be as detailed as you can with your prompts, specifying what’s happening in the scene, how your characters should move, the style the video should be in, where the camera is positioned, and so on.
Clips created with Veo 3, which are limited to eight seconds, also come with sound attached: you might want to give some instructions here too, otherwise the video generator will fill the silence with something generic.
While the AI video generation technology in Google Veo 3 is undoubtedly impressive, it’s far from perfect – there are often plenty of weird glitches on show. For the next couple of days, you can take a look for yourself.